In TypeName::GetFullyQualifiedType, strip SubstTemplateTypeParmType.

When the type comes (directly or indirectly) from being used as a template paramater, it is decorated
by SubstTemplateTypeParmType which gets in the way of properly getting the name correct (leads to
'std::const string'.

lib/Utils/AST.cpp

@@ -1515,6 +1515,19 @@ namespace utils {
       return QT;
     }
 
+    // Remove the part of the type related to the type being a template
+    // parameter (we won't report it as part of the 'type name' and it is
+    // actually make the code below to be more complex (to handle those)
+    while (isa<SubstTemplateTypeParmType>(QT.getTypePtr())) {
+      // Get the qualifiers.
+      Qualifiers quals = QT.getQualifiers();
+
+      QT = dyn_cast<SubstTemplateTypeParmType>(QT.getTypePtr())->desugar();
+
+      // Add back the qualifiers.
+      QT = Ctx.getQualifiedType(QT, quals);
+    }
+
     NestedNameSpecifier* prefix = 0;
     Qualifiers prefix_qualifiers;
     if (const ElaboratedType* etype_input