pinctrl: rzn1: Add of_node_put() before return
Each iteration of for_each_child_of_node puts the previous node, but in the case of a return from the middle of the loop, there is no put, thus causing a memory leak. Hence add an of_node_put before the return in three places. Issue found with Coccinelle. Signed-off-by: Nishka Dasgupta <nishkadg.linux@gmail.com> Signed-off-by: Geert Uytterhoeven <geert+renesas@glider.be>
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@ -412,8 +412,10 @@ static int rzn1_dt_node_to_map(struct pinctrl_dev *pctldev,
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for_each_child_of_node(np, child) {
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ret = rzn1_dt_node_to_map_one(pctldev, child, map, num_maps);
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if (ret < 0)
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if (ret < 0) {
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of_node_put(child);
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return ret;
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}
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}
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return 0;
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@ -792,8 +794,10 @@ static int rzn1_pinctrl_parse_functions(struct device_node *np,
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grp = &ipctl->groups[ipctl->ngroups];
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grp->func = func->name;
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ret = rzn1_pinctrl_parse_groups(child, grp, ipctl);
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if (ret < 0)
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if (ret < 0) {
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of_node_put(child);
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return ret;
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}
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i++;
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ipctl->ngroups++;
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}
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@ -838,8 +842,10 @@ static int rzn1_pinctrl_probe_dt(struct platform_device *pdev,
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for_each_child_of_node(np, child) {
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ret = rzn1_pinctrl_parse_functions(child, ipctl, i++);
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if (ret < 0)
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if (ret < 0) {
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of_node_put(child);
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return ret;
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}
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}
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return 0;
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