pinctrl: rzn1: Add of_node_put() before return

Each iteration of for_each_child_of_node puts the previous node, but in
the case of a return from the middle of the loop, there is no put, thus
causing a memory leak. Hence add an of_node_put before the return in
three places.
Issue found with Coccinelle.

Signed-off-by: Nishka Dasgupta <nishkadg.linux@gmail.com>
Signed-off-by: Geert Uytterhoeven <geert+renesas@glider.be>
This commit is contained in:
Nishka Dasgupta 2019-08-04 21:10:29 +05:30 committed by Geert Uytterhoeven
parent 5f9e832c13
commit 2f64dc70ba

View File

@ -412,9 +412,11 @@ static int rzn1_dt_node_to_map(struct pinctrl_dev *pctldev,
for_each_child_of_node(np, child) {
ret = rzn1_dt_node_to_map_one(pctldev, child, map, num_maps);
if (ret < 0)
if (ret < 0) {
of_node_put(child);
return ret;
}
}
return 0;
}
@ -792,8 +794,10 @@ static int rzn1_pinctrl_parse_functions(struct device_node *np,
grp = &ipctl->groups[ipctl->ngroups];
grp->func = func->name;
ret = rzn1_pinctrl_parse_groups(child, grp, ipctl);
if (ret < 0)
if (ret < 0) {
of_node_put(child);
return ret;
}
i++;
ipctl->ngroups++;
}
@ -838,9 +842,11 @@ static int rzn1_pinctrl_probe_dt(struct platform_device *pdev,
for_each_child_of_node(np, child) {
ret = rzn1_pinctrl_parse_functions(child, ipctl, i++);
if (ret < 0)
if (ret < 0) {
of_node_put(child);
return ret;
}
}
return 0;
}