btrfs: factor out block-mapping for RAID0
Now that we have a container for the I/O geometry that has all the needed information for the block mappings of RAID0, factor out a helper calculating this information. Signed-off-by: Johannes Thumshirn <johannes.thumshirn@wdc.com> Reviewed-by: David Sterba <dsterba@suse.com> Signed-off-by: David Sterba <dsterba@suse.com>
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@ -6362,6 +6362,15 @@ static bool is_single_device_io(struct btrfs_fs_info *fs_info,
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return true;
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}
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static void map_blocks_raid0(const struct btrfs_chunk_map *map,
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struct btrfs_io_geometry *io_geom)
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{
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io_geom->stripe_index = io_geom->stripe_nr % map->num_stripes;
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io_geom->stripe_nr /= map->num_stripes;
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if (io_geom->op == BTRFS_MAP_READ)
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io_geom->mirror_num = 1;
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}
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/*
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* Map one logical range to one or more physical ranges.
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*
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@ -6449,10 +6458,7 @@ int btrfs_map_block(struct btrfs_fs_info *fs_info, enum btrfs_map_op op,
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up_read(&dev_replace->rwsem);
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if (map->type & BTRFS_BLOCK_GROUP_RAID0) {
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io_geom.stripe_index = io_geom.stripe_nr % map->num_stripes;
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io_geom.stripe_nr /= map->num_stripes;
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if (op == BTRFS_MAP_READ)
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io_geom.mirror_num = 1;
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map_blocks_raid0(map, &io_geom);
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} else if (map->type & BTRFS_BLOCK_GROUP_RAID1_MASK) {
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if (op != BTRFS_MAP_READ) {
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io_geom.num_stripes = map->num_stripes;
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