Btrfs: devid filter
Relocate chunks which have at least one stripe located on a device with devid X. Signed-off-by: Ilya Dryomov <idryomov@gmail.com>
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@ -2150,6 +2150,23 @@ static int chunk_usage_filter(struct btrfs_fs_info *fs_info, u64 chunk_offset,
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return ret;
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}
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static int chunk_devid_filter(struct extent_buffer *leaf,
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struct btrfs_chunk *chunk,
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struct btrfs_balance_args *bargs)
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{
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struct btrfs_stripe *stripe;
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int num_stripes = btrfs_chunk_num_stripes(leaf, chunk);
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int i;
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for (i = 0; i < num_stripes; i++) {
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stripe = btrfs_stripe_nr(chunk, i);
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if (btrfs_stripe_devid(leaf, stripe) == bargs->devid)
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return 0;
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}
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return 1;
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}
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static int should_balance_chunk(struct btrfs_root *root,
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struct extent_buffer *leaf,
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struct btrfs_chunk *chunk, u64 chunk_offset)
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@ -2183,6 +2200,12 @@ static int should_balance_chunk(struct btrfs_root *root,
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return 0;
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}
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/* devid filter */
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if ((bargs->flags & BTRFS_BALANCE_ARGS_DEVID) &&
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chunk_devid_filter(leaf, chunk, bargs)) {
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return 0;
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}
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return 1;
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}
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@ -201,6 +201,7 @@ struct map_lookup {
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*/
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#define BTRFS_BALANCE_ARGS_PROFILES (1ULL << 0)
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#define BTRFS_BALANCE_ARGS_USAGE (1ULL << 1)
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#define BTRFS_BALANCE_ARGS_DEVID (1ULL << 2)
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struct btrfs_balance_args;
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struct btrfs_balance_control {
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