rcu/tree: Remove superfluous return from void call_rcu* functions

The return keyword is not needed here.

Signed-off-by: Joel Fernandes (Google) <joel@joelfernandes.org>
Signed-off-by: Paul E. McKenney <paulmck@kernel.org>
Signed-off-by: Frederic Weisbecker <frederic@kernel.org>
This commit is contained in:
Joel Fernandes (Google) 2023-07-29 14:27:36 +00:00 committed by Frederic Weisbecker
parent f0a31b26be
commit 4502138acc

View File

@ -2713,7 +2713,7 @@ __call_rcu_common(struct rcu_head *head, rcu_callback_t func, bool lazy_in)
*/
void call_rcu_hurry(struct rcu_head *head, rcu_callback_t func)
{
return __call_rcu_common(head, func, false);
__call_rcu_common(head, func, false);
}
EXPORT_SYMBOL_GPL(call_rcu_hurry);
#endif
@ -2764,7 +2764,7 @@ EXPORT_SYMBOL_GPL(call_rcu_hurry);
*/
void call_rcu(struct rcu_head *head, rcu_callback_t func)
{
return __call_rcu_common(head, func, IS_ENABLED(CONFIG_RCU_LAZY));
__call_rcu_common(head, func, IS_ENABLED(CONFIG_RCU_LAZY));
}
EXPORT_SYMBOL_GPL(call_rcu);