rcu/tree: Remove superfluous return from void call_rcu* functions
The return keyword is not needed here. Signed-off-by: Joel Fernandes (Google) <joel@joelfernandes.org> Signed-off-by: Paul E. McKenney <paulmck@kernel.org> Signed-off-by: Frederic Weisbecker <frederic@kernel.org>
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@ -2713,7 +2713,7 @@ __call_rcu_common(struct rcu_head *head, rcu_callback_t func, bool lazy_in)
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*/
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void call_rcu_hurry(struct rcu_head *head, rcu_callback_t func)
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{
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return __call_rcu_common(head, func, false);
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__call_rcu_common(head, func, false);
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}
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EXPORT_SYMBOL_GPL(call_rcu_hurry);
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#endif
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@ -2764,7 +2764,7 @@ EXPORT_SYMBOL_GPL(call_rcu_hurry);
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*/
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void call_rcu(struct rcu_head *head, rcu_callback_t func)
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{
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return __call_rcu_common(head, func, IS_ENABLED(CONFIG_RCU_LAZY));
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__call_rcu_common(head, func, IS_ENABLED(CONFIG_RCU_LAZY));
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}
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EXPORT_SYMBOL_GPL(call_rcu);
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