cpufreq: e_powersaver: Use struct_size() in kzalloc()

One of the more common cases of allocation size calculations is
finding the size of a structure that has a zero-sized array at
the end, along with memory for some number of elements for that
array. For example:

struct foo {
    int stuff;
    void *entry[];
};

instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL);

Instead of leaving these open-coded and prone to type mistakes, we
can now use the new struct_size() helper:

instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL);

This code was detected with the help of Coccinelle.

Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com>
Acked-by: Viresh Kumar <viresh.kumar@linaro.org>
Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@intel.com>
This commit is contained in:
Gustavo A. R. Silva 2019-01-07 11:33:43 -06:00 committed by Rafael J. Wysocki
parent 21469df467
commit 4944514e6c

View File

@ -323,9 +323,8 @@ static int eps_cpu_init(struct cpufreq_policy *policy)
states = 2;
/* Allocate private data and frequency table for current cpu */
centaur = kzalloc(sizeof(*centaur)
+ (states + 1) * sizeof(struct cpufreq_frequency_table),
GFP_KERNEL);
centaur = kzalloc(struct_size(centaur, freq_table, states + 1),
GFP_KERNEL);
if (!centaur)
return -ENOMEM;
eps_cpu[0] = centaur;