cpufreq: e_powersaver: Use struct_size() in kzalloc()
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; void *entry[]; }; instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL); This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com> Acked-by: Viresh Kumar <viresh.kumar@linaro.org> Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@intel.com>
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@ -323,9 +323,8 @@ static int eps_cpu_init(struct cpufreq_policy *policy)
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states = 2;
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/* Allocate private data and frequency table for current cpu */
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centaur = kzalloc(sizeof(*centaur)
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+ (states + 1) * sizeof(struct cpufreq_frequency_table),
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GFP_KERNEL);
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centaur = kzalloc(struct_size(centaur, freq_table, states + 1),
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GFP_KERNEL);
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if (!centaur)
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return -ENOMEM;
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eps_cpu[0] = centaur;
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