udf: Drop pointless check from udf_sync_fs()
The check if (bh) in udf_sync_fs() is pointless as we cannot have sbi->s_lvid_dirty and !sbi->s_lvid_bh (as already asserted by udf_updated_lvid()). So just drop the pointless check. Reviewed-by: Steven J. Magnani <steve@digidescorp.com> Reported-by: Colin Ian King <colin.king@canonical.com> Signed-off-by: Jan Kara <jack@suse.cz>
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@ -2330,13 +2330,10 @@ static int udf_sync_fs(struct super_block *sb, int wait)
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mutex_lock(&sbi->s_alloc_mutex);
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mutex_lock(&sbi->s_alloc_mutex);
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if (sbi->s_lvid_dirty) {
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if (sbi->s_lvid_dirty) {
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struct buffer_head *bh = sbi->s_lvid_bh;
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struct buffer_head *bh = sbi->s_lvid_bh;
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struct logicalVolIntegrityDesc *lvid;
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if (bh) {
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lvid = (struct logicalVolIntegrityDesc *)bh->b_data;
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struct logicalVolIntegrityDesc *lvid;
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udf_finalize_lvid(lvid);
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lvid = (struct logicalVolIntegrityDesc *)bh->b_data;
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udf_finalize_lvid(lvid);
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}
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/*
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/*
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* Blockdevice will be synced later so we don't have to submit
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* Blockdevice will be synced later so we don't have to submit
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