sock: fix lockdep annotation in release_sock
During release_sock we use callbacks to finish the processing of outstanding skbs on the socket. We actually are still locked, sk_locked.owned == 1, but we already told lockdep that the mutex is released. This could lead to false positives in lockdep for lockdep_sock_is_held (we don't hold the slock spinlock during processing the outstanding skbs). I took over this patch from Eric Dumazet and tested it. Signed-off-by: Eric Dumazet <eric.dumazet@gmail.com> Signed-off-by: Hannes Frederic Sowa <hannes@stressinduktion.org> Signed-off-by: David S. Miller <davem@davemloft.net>
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@ -1333,7 +1333,12 @@ static inline void sk_wmem_free_skb(struct sock *sk, struct sk_buff *skb)
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static inline void sock_release_ownership(struct sock *sk)
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static inline void sock_release_ownership(struct sock *sk)
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{
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{
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sk->sk_lock.owned = 0;
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if (sk->sk_lock.owned) {
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sk->sk_lock.owned = 0;
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/* The sk_lock has mutex_unlock() semantics: */
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mutex_release(&sk->sk_lock.dep_map, 1, _RET_IP_);
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}
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}
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}
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/*
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/*
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@ -2483,11 +2483,6 @@ EXPORT_SYMBOL(lock_sock_nested);
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void release_sock(struct sock *sk)
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void release_sock(struct sock *sk)
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{
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{
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/*
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* The sk_lock has mutex_unlock() semantics:
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*/
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mutex_release(&sk->sk_lock.dep_map, 1, _RET_IP_);
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spin_lock_bh(&sk->sk_lock.slock);
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spin_lock_bh(&sk->sk_lock.slock);
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if (sk->sk_backlog.tail)
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if (sk->sk_backlog.tail)
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__release_sock(sk);
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__release_sock(sk);
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