arm64: swiotlb: Reduce the default size if no ZONE_DMA bouncing needed
With CONFIG_DMA_BOUNCE_UNALIGNED_KMALLOC enabled, the arm64 kernel still allocates the default SWIOTLB buffer (64MB) even if ZONE_DMA is disabled or all the RAM fits into this zone. However, this potentially wastes a non-negligible amount of memory on platforms with little RAM. Reduce the SWIOTLB size to 1MB per 1GB of RAM if only needed for kmalloc() buffer bouncing. Signed-off-by: Catalin Marinas <catalin.marinas@arm.com> Suggested-by: Ross Burton <ross.burton@arm.com> Cc: Ross Burton <ross.burton@arm.com> Cc: Will Deacon <will@kernel.org> Reviewed-by: Robin Murphy <robin.murphy@arm.com>
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@ -16,6 +16,7 @@
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#include <linux/nodemask.h>
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#include <linux/initrd.h>
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#include <linux/gfp.h>
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#include <linux/math.h>
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#include <linux/memblock.h>
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#include <linux/sort.h>
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#include <linux/of.h>
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@ -493,8 +494,16 @@ void __init mem_init(void)
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{
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bool swiotlb = max_pfn > PFN_DOWN(arm64_dma_phys_limit);
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if (IS_ENABLED(CONFIG_DMA_BOUNCE_UNALIGNED_KMALLOC))
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if (IS_ENABLED(CONFIG_DMA_BOUNCE_UNALIGNED_KMALLOC) && !swiotlb) {
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/*
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* If no bouncing needed for ZONE_DMA, reduce the swiotlb
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* buffer for kmalloc() bouncing to 1MB per 1GB of RAM.
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*/
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unsigned long size =
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DIV_ROUND_UP(memblock_phys_mem_size(), 1024);
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swiotlb_adjust_size(min(swiotlb_size_or_default(), size));
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swiotlb = true;
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}
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swiotlb_init(swiotlb, SWIOTLB_VERBOSE);
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