fanotify: Fix the checks in fanotify_fsid_equal
Clang warns: fs/notify/fanotify/fanotify.c:28:23: warning: self-comparison always evaluates to true [-Wtautological-compare] return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1]; ^ fs/notify/fanotify/fanotify.c:28:57: warning: self-comparison always evaluates to true [-Wtautological-compare] return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1]; ^ 2 warnings generated. The intention was clearly to compare val[0] and val[1] in the two different fsid structs. Fix it otherwise this function always returns true. Fixes: afc894c784c8 ("fanotify: Store fanotify handles differently") Link: https://github.com/ClangBuiltLinux/linux/issues/952 Link: https://lore.kernel.org/r/20200327171030.30625-1-natechancellor@gmail.com Signed-off-by: Nathan Chancellor <natechancellor@gmail.com> Reviewed-by: Nick Desaulniers <ndesaulniers@google.com> Signed-off-by: Jan Kara <jack@suse.cz>
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@ -25,7 +25,7 @@ static bool fanotify_path_equal(struct path *p1, struct path *p2)
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static inline bool fanotify_fsid_equal(__kernel_fsid_t *fsid1,
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__kernel_fsid_t *fsid2)
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{
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return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
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return fsid1->val[0] == fsid2->val[0] && fsid1->val[1] == fsid2->val[1];
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}
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static bool fanotify_fh_equal(struct fanotify_fh *fh1,
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