task_work: unconditionally run task_work from get_signal()
[ Upstream commit 35d0b389f3b23439ad15b610d6e43fc72fc75779 ] Song reported a boot regression in a kvm image with 5.11-rc, and bisected it down to the below patch. Debugging this issue, turns out that the boot stalled when a task is waiting on a pipe being released. As we no longer run task_work from get_signal() unless it's queued with TWA_SIGNAL, the task goes idle without running the task_work. This prevents ->release() from being called on the pipe, which another boot task is waiting on. For now, re-instate the unconditional task_work run from get_signal(). For 5.12, we'll collapse TWA_RESUME and TWA_SIGNAL, as it no longer makes sense to have a distinction between the two. This will turn task_work notification into a simple boolean, whether to notify or not. Fixes: 98b89b649fce ("signal: kill JOBCTL_TASK_WORK") Reported-by: Song Liu <songliubraving@fb.com> Tested-by: John Stultz <john.stultz@linaro.org> Tested-by: Douglas Anderson <dianders@chromium.org> Tested-by: Sedat Dilek <sedat.dilek@gmail.com> # LLVM/Clang version 11.0.1 Signed-off-by: Jens Axboe <axboe@kernel.dk> Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
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@ -2520,6 +2520,9 @@ bool get_signal(struct ksignal *ksig)
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struct signal_struct *signal = current->signal;
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int signr;
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if (unlikely(current->task_works))
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task_work_run();
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/*
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* For non-generic architectures, check for TIF_NOTIFY_SIGNAL so
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* that the arch handlers don't all have to do it. If we get here
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