ipw2x00: Use struct_size helper instead of open-coded arithmetic
Dynamic size calculations (especially multiplication) should not be performed in memory allocator function arguments due to the risk of them overflowing. This could lead to values wrapping around and a smaller allocation being made than the caller was expecting. Using those allocations could lead to linear overflows of heap memory and other misbehaviors. To avoid this scenario, use the struct_size helper. Signed-off-by: Len Baker <len.baker@gmx.com> Signed-off-by: Kalle Valo <kvalo@codeaurora.org> Link: https://lore.kernel.org/r/20210717142513.5411-1-len.baker@gmx.com
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@ -179,8 +179,8 @@ static struct libipw_txb *libipw_alloc_txb(int nr_frags, int txb_size,
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{
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struct libipw_txb *txb;
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int i;
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txb = kmalloc(sizeof(struct libipw_txb) + (sizeof(u8 *) * nr_frags),
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gfp_mask);
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txb = kmalloc(struct_size(txb, fragments, nr_frags), gfp_mask);
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if (!txb)
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return NULL;
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