gpu: host1x: Show all allocated syncpts via debugfs
When the host1x syncpts status is dumped via the debugfs, syncpts that have been allocated but not yet used are not shown and so currently it is not possible to see all the allocated syncpts. Update the path for dumping the syncpt status via the debugfs to show all allocated syncpts even if they have not been used yet. Note that when the syncpt status is dumped by the kernel itself for debugging only the active syncpt are shown. Signed-off-by: Jon Hunter <jonathanh@nvidia.com> Signed-off-by: Thierry Reding <treding@nvidia.com>
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@ -75,7 +75,7 @@ static int show_channel(struct host1x_channel *ch, void *data, bool show_fifo)
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return 0;
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}
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static void show_syncpts(struct host1x *m, struct output *o)
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static void show_syncpts(struct host1x *m, struct output *o, bool show_all)
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{
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struct list_head *pos;
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unsigned int i;
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@ -97,7 +97,10 @@ static void show_syncpts(struct host1x *m, struct output *o)
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waiters++;
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spin_unlock(&m->syncpt[i].intr.lock);
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if (!min && !max && !waiters)
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if (!kref_read(&m->syncpt[i].ref))
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continue;
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if (!show_all && !min && !max && !waiters)
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continue;
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host1x_debug_output(o,
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@ -124,7 +127,7 @@ static void show_all(struct host1x *m, struct output *o, bool show_fifo)
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unsigned int i;
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host1x_hw_show_mlocks(m, o);
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show_syncpts(m, o);
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show_syncpts(m, o, true);
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host1x_debug_output(o, "---- channels ----\n");
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for (i = 0; i < m->info->nb_channels; ++i) {
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@ -241,5 +244,5 @@ void host1x_debug_dump_syncpts(struct host1x *host1x)
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.fn = write_to_printk
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};
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show_syncpts(host1x, &o);
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show_syncpts(host1x, &o, false);
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}
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