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sched: Simplify the free path some

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If we check the root_domain reference count we can see if its been
used or not, use this observation to simplify some of the return
paths.

Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl>
Cc: Mike Galbraith <efault@gmx.de>
Cc: Nick Piggin <npiggin@kernel.dk>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Andrew Morton <akpm@linux-foundation.org>
Link: http://lkml.kernel.org/r/20110407122942.298339503@chello.nl
Signed-off-by: Ingo Molnar <mingo@elte.hu>
This commit is contained in:
Peter Zijlstra 2011-04-07 14:09:51 +02:00 committed by Ingo Molnar
parent dce840a087
commit 822ff793c3
1 changed files with 5 additions and 6 deletions
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11
kernel/sched.c
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@ -7023,7 +7023,8 @@ static void __free_domain_allocs(struct s_data *d, enum s_alloc what,
switch (what) {
case sa_rootdomain:
free_rootdomain(&d->rd->rcu); /* fall through */
if (!atomic_read(&d->rd->refcount))
free_rootdomain(&d->rd->rcu); /* fall through */
case sa_sd:
free_percpu(d->sd); /* fall through */
case sa_sd_storage:
@ -7208,7 +7209,7 @@ static int build_sched_domains(const struct cpumask *cpu_map,
enum s_alloc alloc_state = sa_none;
struct sched_domain *sd;
struct s_data d;
int i;
int i, ret = -ENOMEM;
alloc_state = __visit_domain_allocation_hell(&d, cpu_map);
if (alloc_state != sa_rootdomain)
@ -7261,12 +7262,10 @@ static int build_sched_domains(const struct cpumask *cpu_map,
}
rcu_read_unlock();
__free_domain_allocs(&d, sa_sd, cpu_map);
return 0;
ret = 0;
error:
__free_domain_allocs(&d, alloc_state, cpu_map);
return -ENOMEM;
return ret;
}
static cpumask_var_t *doms_cur; /* current sched domains */