btrfs: tag as unlikely the key comparison when checking sibling keys
When checking siblings keys, before moving keys from one node/leaf to a sibling node/leaf, it's very unexpected to have the last key of the left sibling greater than or equals to the first key of the right sibling, as that means we have a (serious) corruption that breaks the key ordering properties of a b+tree. Since this is unexpected, surround the comparison with the unlikely macro, which helps the compiler generate better code for the most expected case (no existing b+tree corruption). This is also what we do for other unexpected cases of invalid key ordering (like at btrfs_set_item_key_safe()). Reviewed-by: Qu Wenruo <wqu@suse.com> Signed-off-by: Filipe Manana <fdmanana@suse.com> Reviewed-by: David Sterba <dsterba@suse.com> Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
parent
f2db4d5cb4
commit
88ad95b055
@ -2707,7 +2707,7 @@ static bool check_sibling_keys(struct extent_buffer *left,
|
||||
btrfs_item_key_to_cpu(right, &right_first, 0);
|
||||
}
|
||||
|
||||
if (btrfs_comp_cpu_keys(&left_last, &right_first) >= 0) {
|
||||
if (unlikely(btrfs_comp_cpu_keys(&left_last, &right_first) >= 0)) {
|
||||
btrfs_crit(left->fs_info, "left extent buffer:");
|
||||
btrfs_print_tree(left, false);
|
||||
btrfs_crit(left->fs_info, "right extent buffer:");
|
||||
|
Loading…
x
Reference in New Issue
Block a user