iio: pressure: zpa2326: use 'time_left' variable with wait_for_completion_interruptible_timeout()

There is a confusing pattern in the kernel to use a variable named 'timeout' to
store the result of wait_for_completion_interruptible_timeout() causing patterns like:

	timeout = wait_for_completion_interruptible_timeout(...)
	if (!timeout) return -ETIMEDOUT;

with all kinds of permutations. Use 'time_left' as a variable to make the code
self explaining.

Signed-off-by: Wolfram Sang <wsa+renesas@sang-engineering.com>
Link: https://lore.kernel.org/r/20240429113313.68359-9-wsa+renesas@sang-engineering.com
Signed-off-by: Jonathan Cameron <Jonathan.Cameron@huawei.com>
This commit is contained in:
Wolfram Sang 2024-04-29 13:33:11 +02:00 committed by Jonathan Cameron
parent b0329b3c7e
commit 8d0c937616

View File

@ -861,13 +861,13 @@ static int zpa2326_wait_oneshot_completion(const struct iio_dev *indio_dev,
struct zpa2326_private *private)
{
unsigned int val;
long timeout;
long time_left;
zpa2326_dbg(indio_dev, "waiting for one shot completion interrupt");
timeout = wait_for_completion_interruptible_timeout(
time_left = wait_for_completion_interruptible_timeout(
&private->data_ready, ZPA2326_CONVERSION_JIFFIES);
if (timeout > 0)
if (time_left > 0)
/*
* Interrupt handler completed before timeout: return operation
* status.
@ -877,10 +877,10 @@ static int zpa2326_wait_oneshot_completion(const struct iio_dev *indio_dev,
/* Clear all interrupts just to be sure. */
regmap_read(private->regmap, ZPA2326_INT_SOURCE_REG, &val);
if (!timeout) {
if (!time_left) {
/* Timed out. */
zpa2326_warn(indio_dev, "no one shot interrupt occurred (%ld)",
timeout);
time_left);
return -ETIME;
}