ice: fix potential double free in probe unrolling
[ Upstream commit bc3a024101ca497bea4c69be4054c32a5c349f1d ] If ice_init_interrupt_scheme fails, ice_probe will jump to clearing up the interrupts. This can lead to some static analysis tools such as the compiler sanitizers complaining about double free problems. Since ice_init_interrupt_scheme already unrolls internally on failure, there is no need to call ice_clear_interrupt_scheme when it fails. Add a new unroll label and use that instead. Signed-off-by: Jacob Keller <jacob.e.keller@intel.com> Tested-by: Andrew Bowers <andrewx.bowers@intel.com> Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com> Signed-off-by: Sasha Levin <sashal@kernel.org>
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@ -2900,7 +2900,7 @@ ice_probe(struct pci_dev *pdev, const struct pci_device_id __always_unused *ent)
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if (err) {
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dev_err(dev, "ice_init_interrupt_scheme failed: %d\n", err);
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err = -EIO;
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goto err_init_interrupt_unroll;
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goto err_init_vsi_unroll;
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}
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/* Driver is mostly up */
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@ -2986,6 +2986,7 @@ err_msix_misc_unroll:
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ice_free_irq_msix_misc(pf);
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err_init_interrupt_unroll:
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ice_clear_interrupt_scheme(pf);
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err_init_vsi_unroll:
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devm_kfree(dev, pf->vsi);
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err_init_pf_unroll:
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ice_deinit_pf(pf);
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