gfs2: Don't clear GBF_FULL flags in rs_deltree
Removing a reservation doesn't make any actual space available, so don't clear the GBF_FULL flags in that case. Otherwise, we'll only spend more time scanning the bitmaps unnecessarily. Signed-off-by: Andreas Gruenbacher <agruenba@redhat.com>
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@ -327,20 +327,6 @@ static bool gfs2_rbm_add(struct gfs2_rbm *rbm, u32 blocks)
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}
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}
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static struct gfs2_bitmap *gfs2_block_to_bitmap(struct gfs2_rgrpd *rgd,
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u64 block)
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{
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unsigned int delta = (sizeof(struct gfs2_rgrp) -
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sizeof(struct gfs2_meta_header)) * GFS2_NBBY;
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unsigned int rblock, bii;
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if (!rgrp_contains_block(rgd, block))
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return NULL;
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rblock = block - rgd->rd_data0;
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bii = (rblock + delta) / rgd->rd_sbd->sd_blocks_per_bitmap;
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return rgd->rd_bits + bii;
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}
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/**
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* gfs2_unaligned_extlen - Look for free blocks which are not byte aligned
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* @rbm: Position to search (value/result)
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@ -660,25 +646,16 @@ static void __rs_deltree(struct gfs2_blkreserv *rs)
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RB_CLEAR_NODE(&rs->rs_node);
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if (rs->rs_free) {
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u64 last_block = rs->rs_start + rs->rs_free - 1;
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struct gfs2_bitmap *start, *last;
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/* return reserved blocks to the rgrp */
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BUG_ON(rs->rs_rgd->rd_reserved < rs->rs_free);
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rs->rs_rgd->rd_reserved -= rs->rs_free;
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/* The rgrp extent failure point is likely not to increase;
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it will only do so if the freed blocks are somehow
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contiguous with a span of free blocks that follows. Still,
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it will force the number to be recalculated later. */
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rgd->rd_extfail_pt += rs->rs_free;
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rs->rs_free = 0;
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start = gfs2_block_to_bitmap(rgd, rs->rs_start);
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last = gfs2_block_to_bitmap(rgd, last_block);
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if (!start || !last)
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return;
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do
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clear_bit(GBF_FULL, &start->bi_flags);
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while (start++ != last);
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}
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}
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