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sched: no need to aggregate task_weight

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We only need to know the task_weight of the busiest rq - nothing to do
if there are no tasks there.

Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl>
Cc: Srivatsa Vaddagiri <vatsa@linux.vnet.ibm.com>
Cc: Mike Galbraith <efault@gmx.de>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
This commit is contained in:
Peter Zijlstra 2008-06-27 13:41:22 +02:00 committed by Ingo Molnar
parent d3f40dbab9
commit a25b5aca87
2 changed files with 2 additions and 16 deletions
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16
kernel/sched.c
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@ -433,12 +433,6 @@ struct cfs_rq {
* The sum of all runqueue weights within this span.
*/
unsigned long rq_weight;
/*
* Weight contributed by tasks; this is the part we can
* influence by moving tasks around.
*/
unsigned long task_weight;
} aggregate;
#endif
#endif
@ -1473,10 +1467,6 @@ static int task_hot(struct task_struct *p, u64 now, struct sched_domain *sd);
* rq_weight:
* Direct sum of all the cpu's their rq weight, e.g. A would get 3 while
* B would get 2.
*
* task_weight:
* Part of the rq_weight contributed by tasks; all groups except B would
* get 1, B gets 2.
*/
static inline struct aggregate_struct *
@ -1524,16 +1514,12 @@ static void
aggregate_group_weight(struct task_group *tg, int cpu, struct sched_domain *sd)
{
unsigned long rq_weight = 0;
unsigned long task_weight = 0;
int i;
for_each_cpu_mask(i, sd->span) {
for_each_cpu_mask(i, sd->span)
rq_weight += tg->cfs_rq[i]->load.weight;
task_weight += tg->cfs_rq[i]->task_weight;
}
aggregate(tg, cpu)->rq_weight = rq_weight;
aggregate(tg, cpu)->task_weight = task_weight;
}
/*

2
kernel/sched_fair.c
View File

@ -1427,7 +1427,7 @@ load_balance_fair(struct rq *this_rq, int this_cpu, struct rq *busiest,
/*
* empty group
*/
if (!aggregate(tg, this_cpu)->task_weight)
if (!tg->cfs_rq[busiest_cpu]->task_weight)
continue;
rem_load = rem_load_move * aggregate(tg, this_cpu)->rq_weight;