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PCI / PM: Skip bridges in pci_enable_wake()

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PCI bridges only have a reason to generate wakeup signals on behalf
of devices below them, so avoid preparing bridges for wakeup directly
in pci_enable_wake().

Also drop the pci_has_subordinate() check from pci_pm_default_resume()
as this will be done by pci_enable_wake() itself now.

Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@intel.com>
Reviewed-by: Mika Westerberg <mika.westerberg@linux.intel.com>
Acked-by: Bjorn Helgaas <bhelgaas@google.com>
This commit is contained in:
Rafael J. Wysocki 2017-07-21 14:38:08 +02:00
parent 16f73eb02d
commit baecc470d5
2 changed files with 8 additions and 3 deletions
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4
drivers/pci/pci-driver.c
View File

@ -647,9 +647,7 @@ static int pci_legacy_resume(struct device *dev)
static void pci_pm_default_resume(struct pci_dev *pci_dev)
{
pci_fixup_device(pci_fixup_resume, pci_dev);
if (!pci_has_subordinate(pci_dev))
pci_enable_wake(pci_dev, PCI_D0, false);
pci_enable_wake(pci_dev, PCI_D0, false);
}
static void pci_pm_default_suspend(struct pci_dev *pci_dev)

7
drivers/pci/pci.c
View File

@ -1912,6 +1912,13 @@ int pci_enable_wake(struct pci_dev *dev, pci_power_t state, bool enable)
{
int ret = 0;
/*
* Bridges can only signal wakeup on behalf of subordinate devices,
* but that is set up elsewhere, so skip them.
*/
if (pci_has_subordinate(dev))
return 0;
/* Don't do the same thing twice in a row for one device. */
if (!!enable == !!dev->wakeup_prepared)
return 0;