sparc: use struct_size() in kzalloc()
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; void *entry[]; }; instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL); This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com> Signed-off-by: David S. Miller <davem@davemloft.net>
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@ -194,8 +194,7 @@ static struct cpuinfo_tree *build_cpuinfo_tree(void)
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n = enumerate_cpuinfo_nodes(tmp_level);
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new_tree = kzalloc(sizeof(struct cpuinfo_tree) +
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(sizeof(struct cpuinfo_node) * n), GFP_ATOMIC);
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new_tree = kzalloc(struct_size(new_tree, nodes, n), GFP_ATOMIC);
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if (!new_tree)
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return NULL;
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