pipe_rdwr_fasync: fix the error handling to prevent the leak/crash

If the second fasync_helper() fails, pipe_rdwr_fasync() returns the error
but leaves the file on ->fasync_readers.

This was always wrong, but since 233e70f422
"saner FASYNC handling on file close" we have the new problem.  Because in
this case setfl() doesn't set FASYNC bit, __fput() will not do
->fasync(0), and we leak fasync_struct with ->fa_file pointing to the
freed file.

Signed-off-by: Oleg Nesterov <oleg@redhat.com>
Cc: Al Viro <viro@ZenIV.linux.org.uk>
Cc: Andi Kleen <andi@firstfloor.org>
Cc: Jonathan Corbet <corbet@lwn.net>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Oleg Nesterov 2009-03-12 14:31:28 -07:00 committed by Linus Torvalds
parent 8d0df7a3d1
commit e5bc49ba74

View File

@ -699,12 +699,12 @@ pipe_rdwr_fasync(int fd, struct file *filp, int on)
int retval; int retval;
mutex_lock(&inode->i_mutex); mutex_lock(&inode->i_mutex);
retval = fasync_helper(fd, filp, on, &pipe->fasync_readers); retval = fasync_helper(fd, filp, on, &pipe->fasync_readers);
if (retval >= 0) {
if (retval >= 0)
retval = fasync_helper(fd, filp, on, &pipe->fasync_writers); retval = fasync_helper(fd, filp, on, &pipe->fasync_writers);
if (retval < 0) /* this can happen only if on == T */
fasync_helper(-1, filp, 0, &pipe->fasync_readers);
}
mutex_unlock(&inode->i_mutex); mutex_unlock(&inode->i_mutex);
if (retval < 0) if (retval < 0)