ext4: fast commit may not fallback for ineligible commit
For the follow scenario: 1. jbd start commit transaction n 2. task A get new handle for transaction n+1 3. task A do some ineligible actions and mark FC_INELIGIBLE 4. jbd complete transaction n and clean FC_INELIGIBLE 5. task A call fsync In this case fast commit will not fallback to full commit and transaction n+1 also not handled by jbd. Make ext4_fc_mark_ineligible() also record transaction tid for latest ineligible case, when call ext4_fc_cleanup() check current transaction tid, if small than latest ineligible tid do not clear the EXT4_MF_FC_INELIGIBLE. Reported-by: kernel test robot <lkp@intel.com> Reported-by: Dan Carpenter <dan.carpenter@oracle.com> Reported-by: Ritesh Harjani <riteshh@linux.ibm.com> Suggested-by: Harshad Shirwadkar <harshadshirwadkar@gmail.com> Signed-off-by: Xin Yin <yinxin.x@bytedance.com> Link: https://lore.kernel.org/r/20220117093655.35160-2-yinxin.x@bytedance.com Signed-off-by: Theodore Ts'o <tytso@mit.edu> Cc: stable@kernel.org
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@ -1749,6 +1749,7 @@ struct ext4_sb_info {
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spinlock_t s_fc_lock;
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struct buffer_head *s_fc_bh;
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struct ext4_fc_stats s_fc_stats;
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tid_t s_fc_ineligible_tid;
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#ifdef CONFIG_EXT4_DEBUG
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int s_fc_debug_max_replay;
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#endif
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@ -2925,7 +2926,7 @@ void __ext4_fc_track_create(handle_t *handle, struct inode *inode,
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struct dentry *dentry);
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void ext4_fc_track_create(handle_t *handle, struct dentry *dentry);
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void ext4_fc_track_inode(handle_t *handle, struct inode *inode);
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void ext4_fc_mark_ineligible(struct super_block *sb, int reason);
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void ext4_fc_mark_ineligible(struct super_block *sb, int reason, handle_t *handle);
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void ext4_fc_start_update(struct inode *inode);
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void ext4_fc_stop_update(struct inode *inode);
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void ext4_fc_del(struct inode *inode);
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