block, bfq: do not idle if only one group is activated
Now that root group is counted into 'num_groups_with_pending_reqs', 'num_groups_with_pending_reqs > 0' is always true in bfq_asymmetric_scenario(). Thus change the condition to '> 1'. On the other hand, this change can enable concurrent sync io if only one group is activated. Signed-off-by: Yu Kuai <yukuai3@huawei.com> Reviewed-by: Jan Kara <jack@suse.cz> Acked-by: Paolo Valente <paolo.valente@linaro.org> Link: https://lore.kernel.org/r/20220916071942.214222-5-yukuai1@huaweicloud.com Signed-off-by: Jens Axboe <axboe@kernel.dk>
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@ -820,7 +820,7 @@ bfq_pos_tree_add_move(struct bfq_data *bfqd, struct bfq_queue *bfqq)
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* much easier to maintain the needed state:
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* 1) all active queues have the same weight,
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* 2) all active queues belong to the same I/O-priority class,
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* 3) there are no active groups.
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* 3) there is at most one active group.
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* In particular, the last condition is always true if hierarchical
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* support or the cgroups interface are not enabled, thus no state
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* needs to be maintained in this case.
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@ -852,7 +852,7 @@ static bool bfq_asymmetric_scenario(struct bfq_data *bfqd,
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return varied_queue_weights || multiple_classes_busy
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#ifdef CONFIG_BFQ_GROUP_IOSCHED
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|| bfqd->num_groups_with_pending_reqs > 0
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|| bfqd->num_groups_with_pending_reqs > 1
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#endif
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;
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}
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