ubifs: work around high stack usage with clang
Building this file with clang can result in large stack usage as seen from this warning: fs/ubifs/auth.c:78:5: error: stack frame size of 1152 bytes in function 'ubifs_prepare_auth_node' The problem is that inlining ubifs_hash_calc_hmac() leads to two SHASH_DESC_ON_STACK() blocks in the same function, and clang for some reason does not reuse the stack space as it should. Putting the first declaration into a separate basic block avoids this problem and reduces the stack allocation to 640 bytes. Signed-off-by: Arnd Bergmann <arnd@arndb.de> Reviewed-by: Nick Desaulniers <ndesaulniers@google.com> Signed-off-by: Richard Weinberger <richard@nod.at>
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@ -78,7 +78,6 @@ static int ubifs_hash_calc_hmac(const struct ubifs_info *c, const u8 *hash,
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int ubifs_prepare_auth_node(struct ubifs_info *c, void *node,
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struct shash_desc *inhash)
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{
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SHASH_DESC_ON_STACK(hash_desc, c->hash_tfm);
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struct ubifs_auth_node *auth = node;
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u8 *hash;
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int err;
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@ -87,13 +86,17 @@ int ubifs_prepare_auth_node(struct ubifs_info *c, void *node,
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if (!hash)
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return -ENOMEM;
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hash_desc->tfm = c->hash_tfm;
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hash_desc->flags = CRYPTO_TFM_REQ_MAY_SLEEP;
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ubifs_shash_copy_state(c, inhash, hash_desc);
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{
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SHASH_DESC_ON_STACK(hash_desc, c->hash_tfm);
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err = crypto_shash_final(hash_desc, hash);
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if (err)
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goto out;
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hash_desc->tfm = c->hash_tfm;
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hash_desc->flags = CRYPTO_TFM_REQ_MAY_SLEEP;
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ubifs_shash_copy_state(c, inhash, hash_desc);
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err = crypto_shash_final(hash_desc, hash);
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if (err)
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goto out;
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}
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err = ubifs_hash_calc_hmac(c, hash, auth->hmac);
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if (err)
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