soc: bcm: brcmstb: Don't leak device tree node reference
[ Upstream commit 1861a7f07e02292830a1ca256328d370deefea30 ] of_find_node_by_path() acquires a reference to the node returned by it and that reference needs to be dropped by its caller. soc_is_brcmstb() doesn't do that, so fix it. [treding: slightly rewrite to avoid inline comparison] Fixes: d52fad262041 ("soc: add stubs for brcmstb SoC's") Signed-off-by: Yangtao Li <tiny.windzz@gmail.com> Signed-off-by: Florian Fainelli <f.fainelli@gmail.com> Signed-off-by: Sasha Levin <sashal@kernel.org>
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@ -31,13 +31,17 @@ static const struct of_device_id brcmstb_machine_match[] = {
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bool soc_is_brcmstb(void)
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{
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const struct of_device_id *match;
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struct device_node *root;
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root = of_find_node_by_path("/");
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if (!root)
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return false;
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return of_match_node(brcmstb_machine_match, root) != NULL;
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match = of_match_node(brcmstb_machine_match, root);
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of_node_put(root);
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return match != NULL;
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}
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static const struct of_device_id sun_top_ctrl_match[] = {
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