This script is used to detect whether a kernel module is written in Rust. It will later be used to disable BTF generation on Rust modules as BTF does not yet support Rust. Reviewed-by: Kees Cook <keescook@chromium.org> Reviewed-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org> Co-developed-by: Alex Gaynor <alex.gaynor@gmail.com> Signed-off-by: Alex Gaynor <alex.gaynor@gmail.com> Co-developed-by: Wedson Almeida Filho <wedsonaf@google.com> Signed-off-by: Wedson Almeida Filho <wedsonaf@google.com> Signed-off-by: Daniel Xu <dxu@dxuuu.xyz> Co-developed-by: Miguel Ojeda <ojeda@kernel.org> Signed-off-by: Miguel Ojeda <ojeda@kernel.org>
		
			
				
	
	
		
			17 lines
		
	
	
		
			565 B
		
	
	
	
		
			Bash
		
	
	
		
			Executable File
		
	
	
	
	
			
		
		
	
	
			17 lines
		
	
	
		
			565 B
		
	
	
	
		
			Bash
		
	
	
		
			Executable File
		
	
	
	
	
| #!/bin/sh
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| # SPDX-License-Identifier: GPL-2.0
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| #
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| # is_rust_module.sh module.ko
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| #
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| # Returns `0` if `module.ko` is a Rust module, `1` otherwise.
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| 
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| set -e
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| 
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| # Using the `16_` prefix ensures other symbols with the same substring
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| # are not picked up (even if it would be unlikely). The last part is
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| # used just in case LLVM decides to use the `.` suffix.
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| #
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| # In the future, checking for the `.comment` section may be another
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| # option, see https://github.com/rust-lang/rust/pull/97550.
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| ${NM} "$*" | grep -qE '^[0-9a-fA-F]+ r _R[^[:space:]]+16___IS_RUST_MODULE[^[:space:]]*$'
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