4efcac3a24
Compute a mask that will only have 0x80 in the bytes which had a zero in them. The formula is: ~(((x & 0x7f7f7f7f) + 0x7f7f7f7f) | x | 0x7f7f7f7f) In the inner word iteration, we have to compute the "x | 0x7f7f7f7f" part, so we can reuse that in the above calculation. Once we have this mask, we perform divide and conquer to find the highest 0x80 location. Signed-off-by: David S. Miller <davem@davemloft.net> |
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boot | ||
configs | ||
include/asm | ||
kernel | ||
lib | ||
math-emu | ||
mm | ||
net | ||
oprofile | ||
prom | ||
Kbuild | ||
Kconfig | ||
Kconfig.debug | ||
Makefile |