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6.5.7(5): The result of E1 >> E2 is E1 right-shifted E2 bit positions.
...
If E1 has a signed type and a negative value, the resulting value
is implementation defined.
So, cast -1 to unsigned type to make result well-defined.
[ Modified to use ~0U based upon recommendation from Al Viro. -DaveM ]
Signed-off-by: Alexey Dobriyan <adobriyan@gmail.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
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