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According to C99 6.3.2.3 it's undefined what happens if a converted pointer is used to call a function whose type is not compatible with the pointed-to type. That's what the qdio code is doing, so fix it. Signed-off-by: Heiko Carstens <heiko.carstens@de.ibm.com> Signed-off-by: Martin Schwidefsky <schwidefsky@de.ibm.com>