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Muxed (mem) regions will wait in request_mem_region_muxed() if the region is busy (in use by another consumer) during the call. In order to wake-up possibly waiting other consumers of the region, it must be released by a release_mem_region() call, which will actually wake up any waiters. release_mem_region() also frees the resource created by request_mem_region_muxed(), avoiding the need for the unmatched kfree(). Signed-off-by: Hans de Goede <hdegoede@redhat.com> Reviewed-by: Andy Shevchenko <andy@kernel.org> Reviewed-by: Mario Limonciello <mario.limonciello@amd.com> Link: https://lore.kernel.org/r/20230711095920.264308-1-hdegoede@redhat.com