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qemu: Remove return value from qemuMonitorDomainJobStatusChangeCallback

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Change the callback prototype and fix the callback registered in the
process code.

Signed-off-by: Peter Krempa <pkrempa@redhat.com>
Reviewed-by: Ján Tomko <jtomko@redhat.com>
This commit is contained in:
Peter Krempa 2021-07-20 10:05:06 +02:00
parent 5bc4f8dd0f
commit 9b69147c05
2 changed files with 6 additions and 7 deletions
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10
src/qemu/qemu_monitor.h
View File

@ -210,11 +210,11 @@ typedef void (*qemuMonitorDomainBlockJobCallback)(qemuMonitor *mon,
int status,
const char *error,
void *opaque);
typedef int (*qemuMonitorDomainJobStatusChangeCallback)(qemuMonitor *mon,
virDomainObj *vm,
const char *jobname,
int status,
void *opaque);
typedef void (*qemuMonitorDomainJobStatusChangeCallback)(qemuMonitor *mon,
virDomainObj *vm,
const char *jobname,
int status,
void *opaque);
typedef int (*qemuMonitorDomainTrayChangeCallback)(qemuMonitor *mon,
virDomainObj *vm,
const char *devAlias,

3
src/qemu/qemu_process.c
View File

@ -977,7 +977,7 @@ qemuProcessHandleBlockJob(qemuMonitor *mon G_GNUC_UNUSED,
}
static int
static void
qemuProcessHandleJobStatusChange(qemuMonitor *mon G_GNUC_UNUSED,
virDomainObj *vm,
const char *jobname,
@ -1034,7 +1034,6 @@ qemuProcessHandleJobStatusChange(qemuMonitor *mon G_GNUC_UNUSED,
cleanup:
qemuProcessEventFree(processEvent);
virObjectUnlock(vm);
return 0;
}