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tests: printf to awk

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Shorten trace logs.
This commit is contained in:
Zdenek Kabelac 2020-09-18 17:27:17 +02:00
parent 9fbcba1c40
commit 4b07ae55f1
2 changed files with 10 additions and 7 deletions
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8
test/shell/integrity-misc.sh
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@ -22,9 +22,11 @@ mkdir -p $mnt
aux prepare_devs 5 64 aux prepare_devs 5 64
printf "%0.sA" {1..16384} >> fileA # Use awk instead of anoyingly long log out from printf
printf "%0.sB" {1..16384} >> fileB #printf "%0.sA" {1..16384} >> fileA
printf "%0.sC" {1..16384} >> fileC awk 'BEGIN { while (z++ < 16384) printf "A" }' > fileA
awk 'BEGIN { while (z++ < 16384) printf "B" }' > fileB
awk 'BEGIN { while (z++ < 16384) printf "C" }' > fileC
# generate random data # generate random data
dd if=/dev/urandom of=randA bs=512K count=2 dd if=/dev/urandom of=randA bs=512K count=2

9
test/shell/integrity.sh
View File

@ -23,10 +23,11 @@ mkdir -p $mnt
aux prepare_devs 5 64 aux prepare_devs 5 64
printf "%0.sA" {1..16384} >> fileA # Use awk instead of anoyingly long log out from printf
# instead of long debug 'printf' log use 'sed' and just replace A->B|C #printf "%0.sA" {1..16384} >> fileA
sed -e 's,A,B,g' fileA > fileB awk 'BEGIN { while (z++ < 16384) printf "A" }' > fileA
sed -e 's,A,C,g' fileA > fileC awk 'BEGIN { while (z++ < 16384) printf "B" }' > fileB
awk 'BEGIN { while (z++ < 16384) printf "C" }' > fileC
# generate random data # generate random data
dd if=/dev/urandom of=randA bs=512K count=2 dd if=/dev/urandom of=randA bs=512K count=2