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systemctl: drop usage of "internally loaded modules"

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I wouldn't know what "internally" is supposed to mean hear, and we use
this terminology in this context nowhere else, so let's drop this.
This commit is contained in:
Lennart Poettering 2013-04-18 02:10:44 +02:00
parent b7253ecda5
commit a5e4972c89
2 changed files with 7 additions and 7 deletions
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8
man/systemctl.xml
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@ -133,12 +133,12 @@ along with systemd; If not, see <http://www.gnu.org/licenses/>.
<term><option>--all</option></term>
<listitem>
<para>When listing units, show all internally loaded units, regardless of
their state, including inactive units. When showing
<para>When listing units, show all loaded units, regardless
of their state, including inactive units. When showing
unit/job/manager properties, show all properties regardless
whether they are set or not.</para>
<para>To list all units installed on disk, use the command
<command>list-unit-files</command> instead.</para>
<para>To list all units installed on the system, use the
<command>list-unit-files</command> command instead.</para>
</listitem>
</varlistentry>

6
src/systemctl/systemctl.c
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@ -4477,9 +4477,9 @@ static int systemctl_help(void) {
" --version Show package version\n"
" -t --type=TYPE List only units of a particular type\n"
" -p --property=NAME Show only properties by this name\n"
" -a --all Show all internally loaded units/properties,\n"
" including dead/empty ones. To list all units installed\n"
" on disk, use the command 'list-unit-files' instead.\n"
" -a --all Show all loaded units/properties, including dead/empty\n"
" ones. To list all units installed on the system, use\n"
" the 'list-unit-files' command instead.\n"
" --failed Show only failed units\n"
" --full Don't ellipsize unit names on output\n"
" --fail When queueing a new job, fail if conflicting jobs are\n"