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meson: catch programs which ignore arguments
Don't try to use <<<. It seems to not work properly with old bash versions or something.
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@ -10,14 +10,20 @@ if "$1" --help | grep -v 'default:' | grep -E -q '.{80}.'; then
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exit 1
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fi
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# --help prints something. Also catches case where args are ignored.
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if ! "$1" --help | grep -q .; then
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echo "$(basename "$1") --help output is empty."
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exit 2
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fi
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# no --help output to stdout
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if "$1" --help 2>&1 1>/dev/null | grep .; then
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echo "$(basename "$1") --help prints to stderr"
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exit 2
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exit 3
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fi
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# error output to stderr
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if ! "$1" --no-such-parameter 2>&1 1>/dev/null | grep -q .; then
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echo "$(basename "$1") with an unknown parameter does not print to stderr"
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exit 3
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exit 4
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fi
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