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meson: catch programs which ignore arguments

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Don't try to use <<<. It seems to not work properly with old bash
versions or something.
This commit is contained in:
Zbigniew Jędrzejewski-Szmek 2019-07-22 10:59:19 +02:00
parent 22d6bea882
commit cdfa3f0c76
1 changed files with 8 additions and 2 deletions
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10
tools/meson-check-help.sh
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@ -10,14 +10,20 @@ if "$1" --help | grep -v 'default:' | grep -E -q '.{80}.'; then
exit 1 exit 1
fi fi
# --help prints something. Also catches case where args are ignored.
if ! "$1" --help | grep -q .; then
echo "$(basename "$1") --help output is empty."
exit 2
fi
# no --help output to stdout # no --help output to stdout
if "$1" --help 2>&1 1>/dev/null | grep .; then if "$1" --help 2>&1 1>/dev/null | grep .; then
echo "$(basename "$1") --help prints to stderr" echo "$(basename "$1") --help prints to stderr"
exit 2 exit 3
fi fi
# error output to stderr # error output to stderr
if ! "$1" --no-such-parameter 2>&1 1>/dev/null | grep -q .; then if ! "$1" --no-such-parameter 2>&1 1>/dev/null | grep -q .; then
echo "$(basename "$1") with an unknown parameter does not print to stderr" echo "$(basename "$1") with an unknown parameter does not print to stderr"
exit 3 exit 4
fi fi