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6febe75da7
While the compiler likely optimizes strlen(x) for string literals,
it is not a constant expression.
Hence,
char buffer[strlen("OPTION_000") + 1];
declares a variable-length array. STRLEN() can be used instead
when a constant espression is needed.
It's not entirely identical to strlen(), as STRLEN("a\0") counts 2.
Also, it only works with string literals and the macro enforces
that the argument is a literal.
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