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timesyncd: fix calculation of transmit time

The kernel timestamp (recv_time) is made earlier than current time
(now_ts), use the timestamp captured before sending packet directly.
This commit is contained in:
Miroslav Lichvar 2014-08-27 16:47:18 +02:00 committed by Kay Sievers
parent 07610e108e
commit 73c76e6330
Notes: Lennart Poettering 2014-10-24 17:40:22 +02:00
Backport: bugfix

View File

@ -500,7 +500,6 @@ static int manager_receive_response(sd_event_source *source, int fd, uint32_t re
.msg_namelen = sizeof(server_addr),
};
struct cmsghdr *cmsg;
struct timespec now_ts;
struct timeval *recv_time;
ssize_t len;
double origin, receive, trans, dest;
@ -613,8 +612,7 @@ static int manager_receive_response(sd_event_source *source, int fd, uint32_t re
* The round-trip delay, d, and system clock offset, t, are defined as:
* d = (T4 - T1) - (T3 - T2) t = ((T2 - T1) + (T3 - T4)) / 2"
*/
assert_se(clock_gettime(clock_boottime_or_monotonic(), &now_ts) >= 0);
origin = tv_to_d(recv_time) - (ts_to_d(&now_ts) - ts_to_d(&m->trans_time_mon)) + OFFSET_1900_1970;
origin = ts_to_d(&m->trans_time) + OFFSET_1900_1970;
receive = ntp_ts_to_d(&ntpmsg.recv_time);
trans = ntp_ts_to_d(&ntpmsg.trans_time);
dest = tv_to_d(recv_time) + OFFSET_1900_1970;