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tdb: detect tdb store of identical records and skip
This can help with ldb where we rewrite the index records
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@ -121,6 +121,7 @@ tdb_off_t tdb_find_lock_hash(struct tdb_context *tdb, TDB_DATA key, uint32_t has
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return rec_ptr;
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}
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static TDB_DATA _tdb_fetch(struct tdb_context *tdb, TDB_DATA key);
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/* update an entry in place - this only works if the new data size
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is <= the old data size and the key exists.
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@ -135,6 +136,25 @@ static int tdb_update_hash(struct tdb_context *tdb, TDB_DATA key, uint32_t hash,
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if (!(rec_ptr = tdb_find(tdb, key, hash, &rec)))
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return -1;
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/* it could be an exact duplicate of what is there - this is
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* surprisingly common (eg. with a ldb re-index). */
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if (rec.key_len == key.dsize &&
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rec.data_len == dbuf.dsize &&
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rec.full_hash == hash) {
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TDB_DATA data = _tdb_fetch(tdb, key);
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if (data.dsize == dbuf.dsize &&
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memcmp(data.dptr, dbuf.dptr, data.dsize) == 0) {
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if (data.dptr) {
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free(data.dptr);
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}
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return 0;
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}
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if (data.dptr) {
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free(data.dptr);
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}
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}
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/* must be long enough key, data and tailer */
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if (rec.rec_len < key.dsize + dbuf.dsize + sizeof(tdb_off_t)) {
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tdb->ecode = TDB_SUCCESS; /* Not really an error */
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