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samba-tool: more conventional usage of parser.parse_args
By default parse_args will use sys.argv[1:], which is to say the command-line without the command name. We have always fed it the equivalent of sys.argv, then trimmed the command off the result. That was a bit silly. Signed-off-by: Douglas Bagnall <douglas.bagnall@catalyst.net.nz> Reviewed-by: Andrew Bartlett <abartlet@samba.org>
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@ -166,9 +166,8 @@ class Command(object):
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def _run(self, *argv):
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parser, optiongroups = self._create_parser(self.command_name)
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opts, args = parser.parse_args([self.command_name] + list(argv))
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opts, args = parser.parse_args(list(argv))
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# Filter out options from option groups
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args = args[1:]
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kwargs = dict(opts.__dict__)
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for option_group in parser.option_groups:
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for option in option_group.option_list:
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@ -288,7 +287,7 @@ class SuperCommand(Command):
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f"{self.command_name} <subcommand> (-h|--help)\n")
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parser, optiongroups = self._create_parser(self.command_name, epilog=epilog)
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opts, args = parser.parse_args([self.command_name] + list(argv))
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opts, args = parser.parse_args(list(argv))
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parser.print_help()
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return -1
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