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find-package (FindByName): in ambigous case, first check if [ path = pkg ]

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This commit is contained in:
Alexey Tourbin 2007-08-10 16:08:53 +04:00
parent bd368155cd
commit 71c3d7908d
1 changed files with 13 additions and 2 deletions
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15
scripts/find-package.in
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@ -195,19 +195,30 @@ FindByName()
# /usr/bin/r pkgA
# /usr/bin/r pkgB
# /usr/sbin/r pkgC
# Remeber that best paths go first, and each package has only the best path.
# Remember that best paths go first, and each package has only the best path.
# Now if the first two paths are the same, we produce raw dependency on /usr/bin/r.
local Verbose=Info
Info "$f: $r indexed by:$(printf %s "$out" |sed -e 's/\t/ -> /; s/$/,/; $s/,$//' |xargs echo '')"
rep="$(IFS=$'\t\n'; set -- $out; printf %s "$1")"
package="$(IFS=$'\t\n'; set -- $out; printf %s "$2")"
# Actually our contents_index generator already handles path dups,
# so the above example is likely to transform into this:
# /usr/bin/r /usr/bin/r
# /usr/sbin/r pkgC
# So we first check if path = package.
if [ "$rep" = "$package" ]; then
Info "$f: $r -> $rep -> $rep (ambiguous, via contents_index_bin)"
printf %s\\n "$rep"
return
fi
# And then we check if the first two paths are the same.
local rep2="$(IFS=$'\t\n'; set -- $out; printf %s "$3")"
if [ "$rep" = "$rep2" ]; then
Info "$f: $r -> $rep -> $rep (raw, ambiguous, via contents_index_bin)"
printf %s\\n "$rep"
return
fi
# However, consdier yet worse real-life case:
# However, consider yet worse real-life case:
# /usr/bin/arpsend arpsend
# /usr/sbin/arpsend vzctl
# In this case, we perfer to put aside the conflict for a while, and query