135 lines
4.3 KiB
Rust
135 lines
4.3 KiB
Rust
use ipfs::Node;
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use libp2p::{multiaddr::Protocol, Multiaddr};
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use std::time::Duration;
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use tokio::time::timeout;
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// Make sure two instances of ipfs can be connected by `Multiaddr`.
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#[tokio::test(max_threads = 1)]
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async fn connect_two_nodes_by_addr() {
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let node_a = Node::new("a").await;
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let node_b = Node::new("b").await;
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let (_, mut b_addrs) = node_b.identity().await.unwrap();
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let b_addr = b_addrs.pop().unwrap();
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timeout(Duration::from_secs(10), node_a.connect(b_addr))
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.await
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.expect("timeout")
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.expect("should've connected");
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}
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// Make sure only a `Multiaddr` with `/p2p/` can be used to connect.
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#[tokio::test(max_threads = 1)]
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#[should_panic(expected = "called `Result::unwrap()` on an `Err` value: MissingProtocolP2p")]
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async fn dont_connect_without_p2p() {
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let node_a = Node::new("a").await;
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let node_b = Node::new("b").await;
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let (_, mut b_addrs) = node_b.identity().await.unwrap();
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let mut b_addr = b_addrs.pop().unwrap();
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// drop the /p2p/peer_id part
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b_addr.pop();
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timeout(Duration::from_secs(10), node_a.connect(b_addr))
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.await
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.expect("timeout")
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.expect_err("should not have connected");
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}
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// Make sure two instances of ipfs can be connected by `PeerId`.
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// Currently ignored, as Ipfs::add_peer (that is necessary in
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// order to connect by PeerId) already performs a dial to the
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// given peer within Pubsub::add_node_to_partial_view it calls
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#[ignore]
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#[tokio::test(max_threads = 1)]
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async fn connect_two_nodes_by_peer_id() {
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let node_a = Node::new("a").await;
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let node_b = Node::new("b").await;
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let (b_key, mut b_addrs) = node_b.identity().await.unwrap();
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let b_id = b_key.into_peer_id();
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let b_id_multiaddr: Multiaddr = format!("/p2p/{}", b_id).parse().unwrap();
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while let Some(addr) = b_addrs.pop() {
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node_a.add_peer(b_id.clone(), addr).await.unwrap();
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}
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timeout(Duration::from_secs(10), node_a.connect(b_id_multiaddr))
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.await
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.expect("timeout")
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.expect("should've connected");
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}
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// Ensure that duplicate connection attempts don't cause hangs.
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#[tokio::test(max_threads = 1)]
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async fn connect_duplicate_multiaddr() {
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let node_a = Node::new("a").await;
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let node_b = Node::new("b").await;
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let (_, mut b_addrs) = node_b.identity().await.unwrap();
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let b_addr = b_addrs.pop().unwrap();
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// test duplicate connections by address
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for _ in 0..3 {
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// final success or failure doesn't matter, there should be no timeout
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let _ = timeout(Duration::from_secs(1), node_a.connect(b_addr.clone()))
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.await
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.unwrap();
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}
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}
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// More complicated one to the above; first node will have two listening addresses and the second
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// one should dial both of the addresses, resulting in two connections.
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#[tokio::test(max_threads = 1)]
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async fn connect_two_nodes_with_two_connections_doesnt_panic() {
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let node_a = Node::new("a").await;
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let node_b = Node::new("b").await;
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node_a
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.add_listening_address(libp2p::build_multiaddr!(Ip4([127, 0, 0, 1]), Tcp(0u16)))
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.await
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.unwrap();
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let addresses = node_a.addrs_local().await.unwrap();
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assert_eq!(
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addresses.len(),
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2,
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"there should have been two local addresses, found {:?}",
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addresses
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);
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let node_a_id = node_a.identity().await.unwrap().0.into_peer_id();
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for mut addr in addresses.into_iter() {
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addr.push(Protocol::P2p(node_a_id.clone().into()));
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timeout(Duration::from_secs(10), node_b.connect(addr))
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.await
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.expect("timeout")
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.expect("should've connected");
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}
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// not too sure on this, since there'll be a single peer but two connections; the return
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// type is `Vec<Connection>` but it's peer with any connection.
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let mut peers = node_a.peers().await.unwrap();
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assert_eq!(
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peers.len(),
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1,
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"there should have been one peer, found {:?}",
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peers
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);
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// sadly we are unable to currently verify that there exists two connections for the node_b
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// peer..
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node_a
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.disconnect(peers.remove(0).addr)
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.await
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.expect("failed to disconnect peer_b at peer_a");
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let peers = node_a.peers().await.unwrap();
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assert!(
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peers.is_empty(),
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"node_b was still connected after disconnect: {:?}",
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peers
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);
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}
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